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0=5k^2+12k+7
We move all terms to the left:
0-(5k^2+12k+7)=0
We add all the numbers together, and all the variables
-(5k^2+12k+7)=0
We get rid of parentheses
-5k^2-12k-7=0
a = -5; b = -12; c = -7;
Δ = b2-4ac
Δ = -122-4·(-5)·(-7)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2}{2*-5}=\frac{10}{-10} =-1 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2}{2*-5}=\frac{14}{-10} =-1+2/5 $
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